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October 30, 2014

October 30, 2014

Posted by **Tyler Stranburg** on Sunday, September 9, 2012 at 5:57pm.

- calculus -
**Damon**, Sunday, September 9, 2012 at 6:13pmdv/dt = k (4 pi r^2) given

v = (4/3) pi r^3 geometry

dv/dr = 4 pi r^2

dv/dt = dv/dr dr/dt = 4 pi r^2 dr/dt

so

k is dr/dt which is constant

dr/dt = (2.9 - 3)/1 = -0.1 in/hr

starts at 3 in

r = 3 - .1(24) = 3-2.4 = 0.6 inches

- calculus -
**Tyler**, Monday, September 10, 2012 at 12:09amcan you solve it with separation of differential equation

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