c= q/m*(delta)T
q= heat or energy, measured in joules (J)
c= specific heat of the substance
m= mass of substance
(delta)T= change in temperature
It requires 14,749 J to heat 75.0 g of water from 20.0 degrees C to 67.0 degrees C?
The correct formula:
q = mcΔT
or c = q/[(m)(ΔT)]
http://chemistry.about.com/od/workedchemistryproblems/a/Specific-Heat-Example-Problem.htm
opps yes your formula is correct!
To find the specific heat (c) of water, we can rearrange the formula and solve for c.
Using the equation c = q / (m * ΔT):
c = q / (m * ΔT)
c = 14,749 J / (75.0 g * (67.0°C - 20.0°C))
First, we need to calculate the change in temperature (ΔT):
ΔT = final temperature - initial temperature
ΔT = 67.0°C - 20.0°C
ΔT = 47.0°C
Now, we can substitute the values into the equation:
c = 14,749 J / (75.0 g * 47.0°C)
Let's calculate:
c = 14,749 J / (3,525 g°C)
Dividing:
c ≈ 4.18 J / g°C
Therefore, the specific heat (c) of water is approximately 4.18 J/g°C.