A boy sledding down a hill accelerates at 1.70 m/s2. If he started from rest, in what distance would he reach a speed of 7.40 m/s?
7.5
To find the distance the boy would reach a speed of 7.40 m/s, we can use the equation of motion:
v^2 = u^2 + 2as
Where:
v = final velocity = 7.40 m/s
u = initial velocity = 0 m/s (since the boy starts from rest)
a = acceleration = 1.70 m/s^2
s = distance
Plugging the given values into the equation, we can solve for s:
7.40^2 = 0^2 + 2 * 1.70 * s
54.76 = 3.40s
Dividing both sides of the equation by 3.40:
s = 54.76 / 3.40
s ≈ 16.10 meters
Therefore, the boy would reach a speed of 7.40 m/s in approximately 16.10 meters.