Sunday

February 1, 2015

February 1, 2015

Posted by **ali** on Saturday, September 8, 2012 at 2:40pm.

1) What is the initial speed of the cannonball?

2) What is the initial angle θ of the cannonball with respect to the ground?

3) What is the maximum height the cannonball goes above the ground?

4) How far from where it was shot will the cannonball land?

5) What is the speed of the cannonball 2.7 seconds after it was shot?

6) How high above the ground is the cannonball 2.7 seconds after it is shot?

- Physics -
**drwls**, Saturday, September 8, 2012 at 4:29pm1) Use the Pythagorean theorem.

Initial Speed = Vo = sqrt [Vx^2 + Vy^2]

2) Launch Angle = arctan(Vyo/Vx)

3) g*Hmax = Vyo^2/2

where Vyo is the initial vertical velocity component.

4) Range = 2*(Vo^2/g)*sinAcosA

5) Use the Pythagorean theorem again, but with the changed value of Vy.

Vy = Vyo - g*t

6) Height = Vyo*t - (g/2)*t^2

**Answer this Question**

**Related Questions**

Physics - A cannonball is shot (from ground level) with an initial horizontal ...

Physics - A cannonball is shot (from ground level) with an initial horizontal ...

Physics - A cannonball is shot (from ground level) with an initial horizontal ...

Physics - A cannonball is shot (from ground level) with an initial horizontal ...

physics - A cannonball is shot (from ground level) with an initial horizontal ...

physics - A cannonball is shot (from ground level) with an initial horizontal ...

Physics - A projectile is shot from the ground at an angle of 60 degrees with ...

Physics - A projectile is shot from the ground at an angle of 60 degrees with ...

Physics - A cannon shoots a cannonball with an initial speed of 25 m/s at an ...

Physics - A cannon shoots a cannonball with an initial speed of 25 m/s at an ...