Posted by ali on Saturday, September 8, 2012 at 2:40pm.
A cannonball is shot (from ground level) with an initial horizontal velocity of 36.0 m/s and an initial vertical velocity of 21.0 m/s.
1) What is the initial speed of the cannonball?
2) What is the initial angle θ of the cannonball with respect to the ground?
3) What is the maximum height the cannonball goes above the ground?
4) How far from where it was shot will the cannonball land?
5) What is the speed of the cannonball 2.7 seconds after it was shot?
6) How high above the ground is the cannonball 2.7 seconds after it is shot?

Physics  drwls, Saturday, September 8, 2012 at 4:29pm
1) Use the Pythagorean theorem.
Initial Speed = Vo = sqrt [Vx^2 + Vy^2]
2) Launch Angle = arctan(Vyo/Vx)
3) g*Hmax = Vyo^2/2
where Vyo is the initial vertical velocity component.
4) Range = 2*(Vo^2/g)*sinAcosA
5) Use the Pythagorean theorem again, but with the changed value of Vy.
Vy = Vyo  g*t
6) Height = Vyo*t  (g/2)*t^2

pyhsics  Anonymous, Wednesday, February 4, 2015 at 1:17pm
88
Answer This Question
Related Questions
 Physics  A cannonball is shot (from ground level) with an initial horizontal ...
 Physics  A cannonball is shot (from ground level) with an initial horizontal ...
 Physics  A cannonball is shot (from ground level) with an initial horizontal ...
 Physics  A cannonball is shot (from ground level) with an initial horizontal ...
 physics  A cannonball is shot (from ground level) with an initial horizontal ...
 physics  A cannonball is shot (from ground level) with an initial horizontal ...
 Physics  A cannon shoots a cannonball with an initial speed of 25 m/s at an ...
 Physics  A cannon shoots a cannonball with an initial speed of 25 m/s at an ...
 Physics  A cannonball is fired with a velocity of 200 m/s at an angle of 25 ...
 Physics  A cannon fires a free projectile at an angle 85 from the ground. The ...
More Related Questions