Tuesday
March 28, 2017

Post a New Question

Posted by on .

an aluminum cylinder is 10.0 cm in length and has a radius of .25 cm. if the mass of a single atom of aluminum is 4.48X10^-23 calculate the number of aluminum atoms present in the cylinder. the density of aluminum is 2.70 g/cm^3

Please answer quickly.

  • chemistry - ,

    g/cm^3 * cm^3 * atoms/g = atoms
    or,
    g/cm^3 * cm^3 รท g/atom = atoms

    2.70 * (pi * .25^2 * 10) / (4.48*10^-23) = 1.18 * 10^23

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question