Posted by **colby** on Thursday, September 6, 2012 at 9:14pm.

A police car is traveling at a velocity of 15.0 m/s due north, when a car zooms by at a constant velocity of 45.0 m/s due north. After a reaction time 0.700 s the policeman begins to pursue the speeder with an acceleration of 3.00 m/s^2. Including the reaction time, how long does it take for the police car to catch up with the speeder?

- physics -
**Willow Newman**, Thursday, September 13, 2012 at 4:55pm
HOW TO:

formula: ΔX=Vi(t)+ 1/2(a)(t^2)

what we know:

Vi= 45.0 m/s

t= .700 s

a= 3.00 m/s^2

NOW PLUG IN:

ΔX=45(.7)+1/2(3)(.7^2)

ΔX= 32.235 m

- physics -
**jj**, Friday, September 25, 2015 at 8:08pm
it's supposed to be time, not distance as answer

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