Posted by **Medusa.** on Thursday, September 6, 2012 at 1:46pm.

An object is thrown from the top of an 80 foot building with an initial velocity of 64 feet per second. The height (h) of the object after (t) seconds is given by the quadratic equation h=-16t+64t+80 .When will the object hit the ground?

- Math -
**Henry**, Friday, September 7, 2012 at 10:48pm
The 16t should be 16t^2. Check your Eq for errors.

d = 64t +16t^2 = 80

16t^2 + 64t - 80 = 0

(T-1)(T+5) = 0.

T = 1, and -s.

T = 1 s.

- Math -
**Henry**, Friday, September 7, 2012 at 10:58pm
Correction:

16t^2 + 64t - 80 = 0

Divide both side by 16:

t^2 + 4t - 5 = 0.

(T-1)(t+5) = 0

T = 1, and -5.

Use positive value of T.

## Answer This Question

## Related Questions

- math - an object is thrown upward from the top of a 80-foot building with a ...
- Math - 13.8.33 Question Help If an object is propelled upward from a height of ...
- Math - In physics, one learns that the height of an object thrown upward from an...
- Maths - object thrown upward from an initial height of h0 feet with an initial ...
- Math - If an object is propelled upward fom a height of s feet at an initial ...
- College Algebra - Use the position equation given below, where s represents the ...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...
- math - A smart-phone is thrown upwards from the top of a 240-foot building with ...
- Math - A ball is thrown downward from the top of a 100-foot building with an ...

More Related Questions