Posted by **Anonymous** on Thursday, September 6, 2012 at 11:00am.

(a) Complete the square by writing in the form . Note: the numbers and can be positive or negative.

x^2-14x-17=(x-7)^2+

(b) Solve the equation by completing the square or using the quadratic formula. If there is more than one correct answer, enter your answers as a comma separated list. If there are no solutions, enter NONE.

x^2-14x-17=0

I keep getting this wrong but I dont know why.help please

- math -
**Reiny**, Thursday, September 6, 2012 at 12:05pm
x^2 - 14x + .... = 17 + ....

x^2 - 14x **+ 49** = 17**+ 49**

(x-7)^2 = 66

x-7 = ± √66

x = 7 ± √66

by formula:

x = (14 ± √(14^2 - 4(1)(-17))/2

= (14 ± √264)/2

= (14 ± 2√66)/2

= 7 ± √66

When the coefficient of x^2 is 1 and the middle term is even, I always use "completing the square" rather than the formula. Notice you get the answer already in simplified form

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