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math

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(a) Complete the square by writing in the form . Note: the numbers and can be positive or negative.

x^2-14x-17=(x-7)^2+

(b) Solve the equation by completing the square or using the quadratic formula. If there is more than one correct answer, enter your answers as a comma separated list. If there are no solutions, enter NONE.

x^2-14x-17=0

I keep getting this wrong but I don't know why.help please

  • math - ,

    x^2 - 14x + .... = 17 + ....
    x^2 - 14x + 49 = 17+ 49
    (x-7)^2 = 66
    x-7 = ± √66
    x = 7 ± √66

    by formula:
    x = (14 ± √(14^2 - 4(1)(-17))/2
    = (14 ± √264)/2
    = (14 ± 2√66)/2
    = 7 ± √66

    When the coefficient of x^2 is 1 and the middle term is even, I always use "completing the square" rather than the formula. Notice you get the answer already in simplified form

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