Homework Help: Physics

Posted by Sara on Thursday, September 6, 2012 at 6:14am.

A swimmer heads directly across a river, swimming at 1.10 m/s relative to the water. She arrives at a point 60.0 m downstream from the point directly across the river, 80.0 m wide. What is the speed of the river current?
What is the swimmer's speed relative to the shore?
In what direction (as an angle relative to a direct line across the river) should the swimmer aim instead, so that she arrives at the point directly opposite her starting point?

Physics - Elena, Thursday, September 6, 2012 at 4:33pm
(a)
s=sqrt(80²+60²) = 100 m.

sinα=60/100=v/1.1.
v=60•1.1/100 = 0.66 m/s.
(b)
sin φ= 0.66/1.1 = 0.06
φ=arcsin 0.06 = 3.44º

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