posted by blah on .
Calcium carbonate can be decomposed by heating according to the equation Below. WHat is the percentage yield of calcium oxide in this reaction if 12.6g of CaO is obtained when 25.9g of CaCO3 is heated ?
CaCO3(S) -> CaO (s) + CO2 (g)
mols CaCO3 = 25.9/molar mass CaCO3.
mols CaO = same as mols CaCO3 according to the balanced equation.
g CaO = mols CaO x molar mass CaO. This is the theoretical yield(TY). The actual yield (AY) is 12.6g
%yield = (AY/TY)*100 = ?