x=0 , x=-8, x=5, x=-5 and x=2
So want to see where the graph of
y = x^2(8+x)(x-5)/ ((x+5)(x-2)) lies above or on the x-axis
investigate the following domains
1. x < -8
2. x between -8 and -5
3. x between -5 and 0
4. x between 0 and 2
5. x between 2 and 5
6. x > 5
You don't actually have to work out the calculations, all you care about is whether the answer is + or -
I will do 5.
a number between 2 and 5, I pick x = 4
(+)(+)(-)/((+)(+)) ≥ 0 ?? , no,
so x between 2 and 5 is not a solution
You can do the others the same way
I also graphed y = x^2(8+x)(x-5)/((x+5)(x-2))
which confirmed that
x<-8 OR -5 < x < 2 OR x > 5
the answer has to be in interval notation, so how would that look?
I am not a big fan of "interval notation"
Back in the dark ages when I taught we used the above notation, which is much more specific
Here is a page that shows "interval notation", look about half way down the page.
It should be quite easy to convert my answer to what you need.
thank you I didnt see this post after you posted that!!! you are truly a life saver!!