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college alg

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solve the following logarithm equation

log (4x+7)=1+log(x-6)

x=?

please show work

  • college alg - ,

    log (4x+7)=1+log(x-6)
    log (4x+7) - log(x-6) = 1
    log [(4x+7)/(x-6)] = 1
    (4x+7)/(x-6) = 10^1 = 10
    10x - 60 = 4x + 7
    6x = 67
    x = 67/6

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