college alg
posted by MYA .
solve the following logarithm equation
log (4x+7)=1+log(x6)
x=?
please show work

log (4x+7)=1+log(x6)
log (4x+7)  log(x6) = 1
log [(4x+7)/(x6)] = 1
(4x+7)/(x6) = 10^1 = 10
10x  60 = 4x + 7
6x = 67
x = 67/6