Posted by **amber** on Wednesday, September 5, 2012 at 7:00pm.

if Y varies jointly as X and the square of Z, and if Y=24 when X=2 and Z=6, find Y when X=10 and Z=9

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**Reiny**, Wednesday, September 5, 2012 at 8:22pm
y = kxz^2 , where k is a constan

given: y = 24, x=2, z=6

24 = k(2)(36)

k = 24/72 = 1/3

y = (1/3)xz^2

when x=10,z=9

y = (1/3)(10)(81) = 10/243

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