math
posted by amber on .
if Y varies jointly as X and the square of Z, and if Y=24 when X=2 and Z=6, find Y when X=10 and Z=9

y = kxz^2 , where k is a constan
given: y = 24, x=2, z=6
24 = k(2)(36)
k = 24/72 = 1/3
y = (1/3)xz^2
when x=10,z=9
y = (1/3)(10)(81) = 10/243