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February 1, 2015

Posted by **ALLI** on Wednesday, September 5, 2012 at 5:27pm.

f(x)=3x+1/8x-9; g(x)=5x/8x-9

(they look like fractions)

A) (f+g)(x)=?

B)domain of (f+g)

c) (f/g)(x)=?

d) domain of f/g?

please show work

- college alg -
**Henry**, Thursday, September 6, 2012 at 8:57pma. (f+g)x = (3x+1)/(8x-9) + 5x/(8x-9) =

(8x+1)/(8x-9).

b. 8x-9 = 0

8x = 9

X = 9/8.

When X = 9/8, the denominator becomes zero and the fraction undefined. Therefore, 9/8 is out of the domain.

Domain = All real values of X except 9/8: 9/8 > X > 9/8.

c. F(x)/G(x) = F(x) * 1/G(x).

F(x)/G(x) = (3x+1)/(8x-9) * (8x-9)/5x=

(3x+1)/5x.

d. The domain = all real values of X:

-Infinity < X < +Infinity.

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