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September 16, 2014

September 16, 2014

Posted by **amber** on Wednesday, September 5, 2012 at 12:45pm.

- algebra -
**Steve**, Wednesday, September 5, 2012 at 12:54pmassuming the barn forms the "length" of each corral, then the total fencing used comprises three widths and two lengths.

Letting x be the width and y the length,

3x + 2y = 310

y = (310-3x)/2

the area of each corral is width * length, so the total area is 2xy

area = 2xy = 2x * (310-3x)/2 = x(310-3x)

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