i)the area of rectangle is x*y (whit x,y side)=>x*y=3200 Ya^2
ii)the condition imposed from the questions is: x+y+y=200 Ya (i have choise two y because the text not exsplicit the misure of one the side):
x+2y=200 => x=200-2y Ya
for (i) (200-2y)*y=3200 Ya^2
200y-2y^2=3200 second-degree equation
you know resolve
let the length of the field by y yds, (parallel to river)
leth the width of the river be x yds
2x + y = 200 ----> y = 200-2x
Second piece of data:
xy = 3200
x(200-2x) = 3200
200x - 2x^2 - 3200 = 0
2x^2 - 200x + 10000 = 10000-3200
x^2 - 100x = 1600
x^2 - 100x + 2500 = 2500-1600
(x-50)^2 = 900
x-50 = ± 30
x = 80 or a negative, which will be rejected
the width is 80 yds and the length is 40
40 + 2(80) = 200
80(40) = 3200
Math - A farmer has determined that a crop of strawberries yields a yearly ...
geometry - A farmer has a triangular field with sides that measure 120 yards, ...
math - The football field is 60 yards by 100 yards.Is the length of the ...
chs - A farmer has a rectangular field with a length of 30 yards and width of x ...
Math - a farmer wants to put a fence around a rectangular field and then divide ...
College Algebra - A farmer wants to build a rectangular fence using the side of ...
math - The spring runoff from melting snow from a certain region is being ...
math ratio - The ratio of the distances a driver and a 2 iron can propel a golf ...
Algebra - Math - A farmer has 100 yards of fencing with which to enclose two ...
Math - The football team had a gain of 4 yards, then a loss of 6 yards, another ...