Posted by Anonymos on .
A circle has the equation
x^2+y^2+6x46=0
graph using (h,k) radius r
A) how do i graph this properly
B) intercept are?

Math 
Bosnian,
x ^ 2 + y ^ 2 + 6 x  46 = 0
x ^ 2 + y ^ 2 + 6 x = 46
( x ^ 2 + 6 x + 9 ) + y ^ 2 = 46 + 9
( x + 3 ) ^ 2 + y ^ 2 = 55
The circle equation is:
(x  a ) ^ 2 + ( y  b ) ^ 2 = r ^ 2
where a and b are the x and y coordinates of the center of the circle.
In this case :
a =  3
becouse :
x + 3 = x  (  3 )
b = 0
Coordinates of the center of the circle :
(  3 , 0 )
Radius r = sqrt ( 55 )
becouse :
sqrt ( 55 ) ^ 2 = 55
y intercept = points when x = 0
In this case :
( 0 + 3 ) ^ 2 + y ^ 2 = 55
9 + y ^ 2 = 55
y ^ 2 = 55  9 = 46
y ^ 2 = 465
y = + OR  sqrt ( 46 )
Coordinates of y intercepts :
0 ,  sqrt ( 46 )
and
0 ,  sqrt ( 46 )
x intercept = points when y = 0
In this case :
( x + 3 ) ^ 2 + 0 ^ 2 = 55
( x + 3 ) ^ 2 = 55
x + 3 = + OR  sqrt ( 55 )
x = + OR  sqrt ( 55 )  3
Coordinates of x intercepts :
 sqrt ( 55 )  3 , 0
and
sqrt ( 55 )  3 , 0