college alg
posted by alli on .
find the equation of a line that is perpendicular to line y=1/6x+6 and contains point (7,0)
y=?
please show work so i can see how its done

slope of y = (1/6)x + 6 is 1/6
so slope of perpendicular is 6
equation is y = 6x + b
but (7,0) lies on it
0 = 6(7) + b
b = 42
y = 6x  42