Tuesday

October 21, 2014

October 21, 2014

Posted by **Amy** on Tuesday, September 4, 2012 at 8:34pm.

1.) (1/15)^2.309

It says hint: set the expression = x and take the logs of both sides.

I did: x=(1/15)^2.309

logx = log(1/15)^2.309 = 2.309 log(1/15)

and I don't know how to proceed or if I'm on the right track.

2.) Find the base x for which

logx (4.44 * 10^4) = 4.44

Hint: write the corresponding exponential expression.

I did 4.44^x = (4.44 * 10^4)

- Logarithms -
**Reiny**, Tuesday, September 4, 2012 at 8:49pmlogx = log(1/15)^2.309 = 2.309 log(1/15)

so far ok

log x = 2.309(-1.17609...)

= -2.71559..

now press the following on your calculator

2ndF or INV

log

=.001924887

check by using the y^{x}key

enter

1÷15

=

y^{x}

2.309

=

you should get .001924887

2.

logx (4.44 * 10^4) = 4.44

so x^4.44 = 4.44 *10^4

log x^4.44 = log(4.44 * 10^4)

4.44 logx = log 4.44 + log 10^4

log x = 4.64738..

x = 44400

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