What is the specific heat of a metal if 24.8 g absorbs 65.7 cal of energy and the temperature rises from 20.2 degrees celsius to 24.5 degrees celsius?
q = mass x specific heat x (Tfinal-Tinitial)
65.7 = 24.8 x sp.h. x (24.5-20.3)
Solve for sp.h.
q = mass x specific heat x (Tfinal-Tinitial) 65.7 = 24.8 x s.h. x (24.5-20.2)
0.616
To determine the specific heat (C) of a metal, you can use the formula:
Q = m * C * ΔT
Where:
Q is the heat energy absorbed (in calories),
m is the mass of the metal (in grams),
C is the specific heat of the metal (in cal/g·°C),
ΔT is the change in temperature (in °C).
In this case, you have:
m = 24.8 g (mass of the metal)
Q = 65.7 cal (heat energy absorbed)
ΔT = 24.5 °C - 20.2 °C (change in temperature)
Plug these values into the formula to solve for C:
65.7 cal = 24.8 g * C * (24.5 °C - 20.2 °C)
First, let's calculate the difference in temperature:
ΔT = 24.5 °C - 20.2 °C = 4.3 °C
Now, plug the values back into the formula:
65.7 cal = 24.8 g * C * 4.3 °C
To solve for C, isolate it:
C = 65.7 cal / (24.8 g * 4.3 °C)
C ≈ 0.742 cal/g·°C
Therefore, the specific heat of the metal is approximately 0.742 cal/g·°C.