Posted by **ppppp** on Tuesday, September 4, 2012 at 4:24pm.

find the x intercepts of a parabola whenthe vertex is at 2,13 and y intercept at 0,5

- math -
**Anonymous**, Tuesday, September 4, 2012 at 5:16pm
the generic equations of parabola is:

y=ax^2+bx+c

by information of the vertex 2;13 i have two facts:

i) 13=a*2^2+b*2+c ....replacing(2;13)

ii)the director of the vertex as equation:

x=-b/2a

by information "intercept at 0,5 ":

iii)5=a*0^2+b*0+c ....replacing(0;5)

tre equation tre unknowns a,b,c

you solve the system

- math -
**KokkoDeRas**, Tuesday, September 4, 2012 at 5:21pm
i forgot to specify in ii) x=-b/(2a) => 2=-b/(2a)

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