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September 19, 2014

September 19, 2014

Posted by **kevin** on Tuesday, September 4, 2012 at 2:30pm.

A stone is thrown vertically downward from the roof of a building. It passes a window 15.0 m below the roof with a speed of 24.3 m/s. It lands on the ground 4.75 s after it was thrown.

(a) What was the initial velocity of the stone?

(b) How tall is the building?

- physics -
**Steve**, Tuesday, September 4, 2012 at 3:10pmIf building has height H, and stone has initial velocity V,

h(t) = H - 15t - 4.9t^2

h(4.75) = 0 = H - 15(4.75) - 4.9*4.75^2

= H - 181.81

so, H = 181.81m

H-15 = H-15t-4.9t^2

t = .794

v(t) = V - 9.8t

-24.3 = V - 9.8*0.794

V = -16.52m/s

- physics -
**kevin**, Tuesday, September 4, 2012 at 3:17pmthanks for the assistance, but apparently none of the answers are correct according to my homework checker.

- physics -
**Elena**, Wednesday, September 5, 2012 at 11:53amh=(v²-vₒ²)/2g,

vₒ= sqrt(v²-2gvh) =

sqrt(24.3²-29.815) = 17.22 m/s.

H=vₒt+gt²/2 =

17.224.75+9.84.75²/2 =192.35 m

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