algebra
posted by brandon on .
(4h1)/1+h; h=2
the 4h1 is on top of 1+h
please can someone explain

you need to know if h>0

sorry.....yes, the 4h1 is on top of 1+h
explain what? 
to evaluate when h=2, just plug in 2 for h everywhere:
(4h1)/(1+h)
(4*21)/(1+2)
7/3 
Okay I get it I was close just didn't now what to do with the negative sign. Thanks for helping