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October 30, 2014

October 30, 2014

Posted by **Anon** on Tuesday, September 4, 2012 at 11:49am.

At what time does the ball reach 10 feet? Round to the nearest tenth.

Step by step please

- Math -
**Steve**, Tuesday, September 4, 2012 at 11:52amh(t) = 48t - 16t^2

so, plug in 10 for h and solve for t:

10 = 48t - 16t^2

8t^2 - 24t + 5 = 0

t = (6±√26)/4

or

t=0.225s (on the way up)

t=2.774s (on the way back down)

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