Posted by Momo on .
A speeder passes a parked police car at a
constant speed of 23.9 m/s. At that instant,
the police car starts from rest with a uniform
acceleration of 2.21 m/s
How much time passes before the speeder
is overtaken by the police car?
Answer in units of s
How far does the speeder travel before being
overtaken by the police car?
Answer in units of m
X1 = 23.9 t
X2 = 1,105 t^2
Set X1 = X2 and solve for t
Then use that t and either equation for the location where they meet.