How much energy (in cal) is required to raise the temperature of 15.0g of isopropyl alcohol from 10.0 C to 25.0 C?
To calculate the amount of energy required to raise the temperature of a substance, you can use the specific heat formula:
Q = mcΔT
Where:
Q is the amount of energy (in calories)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in cal/g°C)
ΔT is the change in temperature (in °C)
In this case, you have:
m = 15.0g (mass of isopropyl alcohol)
c = specific heat capacity of isopropyl alcohol, which is 2.44 cal/g°C (a constant value found in reference tables)
ΔT = final temperature - initial temperature = (25.0°C - 10.0°C) = 15.0°C
Plugging in these values into the formula:
Q = 15.0g × 2.44 cal/g°C × 15.0°C
Now, let's calculate the energy:
Q = 15.0g × 2.44 cal/g°C × 15.0°C
Q = 550.5 cal
Therefore, it would require 550.5 calories of energy to raise the temperature of 15.0g of isopropyl alcohol from 10.0°C to 25.0°C.