The density of acetone, a common solvent found in nail polish remover, is 0.793g/mL. How much acetone (in g) is in a 450-mL bottle? How much acetone (in g) is in a 1.00-wuart bottle?
a.
0.793 g/mL x 450 mL = ?g
b.
What's a 1.0-wuart bottle? Convert 1.0 wuarts to mL, then
0.793 g/mL x mL = grams acetone in a 1.0 wuart bottle.
To find the amount of acetone in a bottle, we can use the formula:
Amount of acetone (in g) = Density of acetone (g/mL) x Volume of the bottle (mL)
For the first question, we are given the density of acetone as 0.793 g/mL, and the volume of the bottle is 450 mL. So, we can plug these values into the formula:
Amount of acetone (in g) = 0.793 g/mL x 450 mL
Now, let's calculate the result:
Amount of acetone (in g) = 356.85 g
Therefore, there are 356.85 grams of acetone in a 450-mL bottle.
For the second question, we need to convert the volume from quarts to milliliters before using the formula.
1 US quart is equal to 946.35 mL, so a 1.00-quart bottle would be equal to:
Volume of the bottle (mL) = 1.00 quart x 946.35 mL/quart
Now, let's calculate the volume of the bottle:
Volume of the bottle (mL) = 946.35 mL
Next, we can use the formula:
Amount of acetone (in g) = 0.793 g/mL x 946.35 mL
Calculating the result:
Amount of acetone (in g) = 750.05 g
Therefore, there are 750.05 grams of acetone in a 1.00-quart bottle.