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March 27, 2015

March 27, 2015

Posted by **Amanda** on Monday, September 3, 2012 at 7:11pm.

north, then turns onto a second highway and continues in a direction of 30◦

north of east for 80 km.

What is her total displacement from the office?

and

At what angle is her displacement? (Consider east to be 0◦ and north 90◦.)

please help! I got 40 and 24.8 and they are both wrong ;(

- physics -
**Elena**, Tuesday, September 4, 2012 at 11:30amthe angle that the second part makes with the first part of the path is 90+30=120º.

Using cosine law,

displacement = sqrt(43² +80²-2•43•80•cos120º) =108 km.

From the sine law

108/sin120 = 80/sinα

sinα=80•sin120/108= 0.64

α =39.9º (the angle which displacement makes with north direction)

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