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March 3, 2015

March 3, 2015

Posted by **Anonymous** on Monday, September 3, 2012 at 6:10pm.

- physics -
**Damon**, Monday, September 3, 2012 at 6:19pmfalls from 500 m with inital Vi = 35

v = Vi + a t so linear in time, average is half of (start + stop)

start v = 35

kinetic energy at ground = (1/2) m (35^2) + m g (500) = (1/2) m v^2

so

v^2 = 9.81 * 1000 + 1225

v = 105 m/s at ground

average v = (35 + 105)/2 = 70 m/s

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