Posted by **Anil** on Monday, September 3, 2012 at 1:57pm.

Ten pounds of liquid water is at a temperature of 180 degrees F at standard atmospheric conditions.

Determine the energy required to convert this to water vapor (steam) at a temperature of 212 degrees F.

- Science -
**DrBob222**, Monday, September 3, 2012 at 2:32pm
Do you want this in BTU?

q1 = heat to move from 180 to 212.

q1 = mass x specific heat x (212-180)

q2 = heat to vaporize water at 212 to steam at 212 F.

q2 = mass x heat vaporization.

Total heat = q1 + q2.

- Science Dr. Bob222 -
**Anil**, Monday, September 3, 2012 at 2:39pm
I don't know how to find the specific heat in q1.

I have q1 = 320 (specific heat)

#2) How do I find heat vaporitzation for q2?

- Science -
**DrBob222**, Monday, September 3, 2012 at 3:33pm
You don't have a table in your text/notes?

specific heat H2O = 1.00 BTU/lb*F

heat vaporization = 970.4 BTU/lb

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