calculus
posted by Don on .
I need help with the following problem: From a point 50 meters from the bottom of a radio tower along level ground, the angle of elevation to the top of the tower is 67 degrees. What is the height of the tower?

think back, back, back to your days in trig.
If the tower has height h,
tan 67 = h/50
h = 117.8 m 
to solve this problem we need trigonometry therefore takes the radiant
67°*3,14/180=1,17 rad.= a
point P=50m
height tower H=?
L=hypotenuse of the right triangle LPH
P=Lcos(a)=> (i)L=p/cos(a)
(ii)H=Lsen(a)
(i)+(ii)H=[p/cs(a)]*sn(a)
tan(a)=sn(a)/cs(a)===>H=p*tan(a)=118m