Posted by **Don** on Monday, September 3, 2012 at 12:03pm.

I need help with the following problem: From a point 50 meters from the bottom of a radio tower along level ground, the angle of elevation to the top of the tower is 67 degrees. What is the height of the tower?

- calculus -
**Steve**, Monday, September 3, 2012 at 12:36pm
think back, back, back to your days in trig.

If the tower has height h,

tan 67 = h/50

h = 117.8 m

- calculus -
**KokkoDeRas**, Monday, September 3, 2012 at 12:52pm
to solve this problem we need trigonometry therefore takes the radiant

67°*3,14/180=1,17 rad.= a

point P=50m

height tower H=?

L=hypotenuse of the right triangle LPH

P=Lcos(a)=> (i)L=p/cos(a)

(ii)H=Lsen(a)

(i)+(ii)H=[p/cs(a)]*sn(a)

tan(a)=sn(a)/cs(a)===>H=p*tan(a)=118m

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