Posted by Don on Monday, September 3, 2012 at 12:03pm.
think back, back, back to your days in trig.
If the tower has height h,
tan 67 = h/50
h = 117.8 m
to solve this problem we need trigonometry therefore takes the radiant
67°*3,14/180=1,17 rad.= a
point P=50m
height tower H=?
L=hypotenuse of the right triangle LPH
P=Lcos(a)=> (i)L=p/cos(a)
(ii)H=Lsen(a)
(i)+(ii)H=[p/cs(a)]*sn(a)
tan(a)=sn(a)/cs(a)===>H=p*tan(a)=118m
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