1.A book and a bookmark together sell for $10.10. If the price of the book is $10 more than the price of the bookmark ,find the price of the book and the price of the bookmark.

bookmark- x book- x+10

equation: 10.10=x+(x+10))

solve for x. then plug in your answer to get the price of the book and the bookmark.

.10

X=10

To solve this problem, let's use algebraic equations.

Let's assume the price of the bookmark is x dollars. According to the given information, the price of the book is $10 more than the price of the bookmark, which means the price of the book is x + $10.

We are also given that the book and bookmark together sell for $10.10. So, we can set up the equation:

x + (x + $10) = $10.10

Now, let's solve for x:

2x + $10 = $10.10

Subtract $10 from both sides:

2x = $10.10 - $10

2x = $0.10

Divide both sides by 2:

x = $0.10 / 2

x = $0.05

So, the price of the bookmark is $0.05.

To find the price of the book, we can substitute this value back into one of the earlier equations:

Price of the book = x + $10 = $0.05 + $10 = $10.05

Therefore, the price of the book is $10.05 and the price of the bookmark is $0.05.