Posted by Anonymous on Monday, September 3, 2012 at 4:43am.
Cooling from 23ºC to -32ºC
ΔL1= α•L•ΔT1 =12•12•10^-3•[23-(-32)]=
=12•12•10^-3•55= 7.92•10^-3 m
Heating from 23ºC to +55ºC
ΔL2= α•L•ΔT2 =12•12•10^-3•[55-23]=
=12•12•10^-3•32= 4.61•10^-3 m
Chamge in the beam’s length is
ΔL=ΔL1+ ΔL2=7.92•10^-3+ 4.61•10^-3=
=1.253•10^-2 m.
Related Questions
Physics - A 53m long steel beam is used to construct the roof of an arena. The ...
Physics - A uniform steel beam of length 5.50 m has a weight of 4.50 103 N. One ...
Physics - An 80kg construction worker sits down 2.0 meters from the end of a ...
physics - find the thermal stress in a 18 ft long steel beam that embedded in ...
physics - find the thermal stress in a 18 ft long steel beam that embedded in ...
Physics - A uniform steel beam of length 5.50 m has a weight of 4.50 103 N. One ...
algebra - The strength of a wood beam varies inversely with its length. A beam ...
physics - A steel beam that is 6.00 m long weighs 332 N. It rests on two ...
physics - A beam of negligible mass of length 3 m is suspended by a string ...
AlgebraII - PLEASE HELP! I DO NOT KNOW WHAT TO DO? The maximum weight that a ...
For Further Reading
