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Posted by **jason** on Monday, September 3, 2012 at 1:41am.

- algebra -
**KokkoDeRas**, Monday, September 3, 2012 at 8:12ami set the equation end give you the solutions but you try to get there

x=first test, y=second test z= three test

i)second test score was 8 points higher than her first score => y=x+8

ii)Her third score was 88=> z=88

iii)B average (between 80=> B=(x+y+z)/3<80

iiii)B average...and 89 inclusive)=> B=(x+y+z)/3>89

advice: replace i and ii in disequations iii and iiii

solution x>72 x<85,50

- algebra -
**KokkoDeRas**, Monday, September 3, 2012 at 8:16amsorry.....errata corrige:

iii)B average (between 80=> B=(x+y+z)/3>80

iiii)B average...and 89 inclusive)=> B=(x+y+z)/3<89

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