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January 28, 2015

January 28, 2015

Posted by **Kristie** on Sunday, September 2, 2012 at 6:07pm.

v = 1/4zxt^2.

The dimensions of the variables v, x, and t are [L]/[T], [L], and [T], respectively. The numerical factor 4 is dimensionless. What must be the dimensions of the variable z, such that both sides of the equation have the same dimensions?

- Physics -
**Damon**, Sunday, September 2, 2012 at 7:10pmL * T^-1 = ? L T^2

? = T^-3

OR DO YOU MEAN???? v = 1/(4zxt^2) ????

L * T^-1 = x^-1 L^-1 T^-2

x^-1 = L^2 T^1

so

L^-2 T^-1

or

1/(L^2T)

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