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Posted by on Sunday, September 2, 2012 at 6:07pm.

Consider the equation
v = 1/4zxt^2.
The dimensions of the variables v, x, and t are [L]/[T], [L], and [T], respectively. The numerical factor 4 is dimensionless. What must be the dimensions of the variable z, such that both sides of the equation have the same dimensions?

  • Physics - , Sunday, September 2, 2012 at 7:10pm

    L * T^-1 = ? L T^2
    ? = T^-3
    OR DO YOU MEAN???? v = 1/(4zxt^2) ????
    L * T^-1 = x^-1 L^-1 T^-2
    x^-1 = L^2 T^1
    so
    L^-2 T^-1
    or
    1/(L^2T)

  • Physics - , Wednesday, July 29, 2015 at 9:19am

    1/[T]3

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