Posted by Fai on .
A flask containing 5ml of 3M hcl solution required 14.45ml of 1M NAOH for titration. How many moles of hcl are present in the solution. The density of 3M hcl is 1.05g/ml
0.005 x 3 = 0.015m
0.01445 x 1 = 0.01445m
Who helps me to solve it
You have two answers. Which is the right one?
Its 0.01445 x 1 = 0.01445 mols HCl because it took 0.01445 mols NaOH to neutralize it. You obviously don't have 5 mL of 3M HCl.