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October 25, 2014

October 25, 2014

Posted by **Miaow** on Sunday, September 2, 2012 at 11:58am.

A commuter backs her car out of her garage with an acceleration of 1.40 m/s2. (a) How long does it take her to reach a speed of 2.00 m/s? (b) If she then brakes to a stop in 0.800 s, what is her deceleration?

a.) V=Vo+at

2.00 m/s = 0 + 1.40 m/s^2t

t = 1.43 seconds

b.) acceleration = v/t

acceleration = (2.00 m/s)/8 s

deceleration = .25 m/s^2

- Physics -
**Henry**, Tuesday, September 4, 2012 at 4:40pma. Correct!

b. Dec. = (Vf-Vo)/t=(0-2) / 0.8=-2.5 m/s^2.

NOTE: Deceleration is always negative.

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