PHYSICS
posted by Noah on .
Assume: A 78 g basketball is launched at an angle of 46.7
◦
and a distance of 18.6 m from
the basketball goal. The ball is released at the
same height (ten feet) as the basketball goal’s
height.
A basketball player tries to make a long
jumpshot as described above.
The acceleration of gravity is 9.8 m/s
2
.
What speed must the player give the ball?
Answer in units of m/s

L=vₒ²•sin2α/g,
vₒ=sqrt(Lg/ sin2α) =sqrt(18.6•93.8/sin93.4) =13.51 m/s