Posted by daisy on Saturday, September 1, 2012 at 7:27pm.
Graph it if you don't understand my solution:
Linear equations follow the format y=mx+b
where m is the slope and b is the y-intercept.
let y= fees and x=number of credits
now calculate slope (change in y/change in x)
m=(2600-2000)/(6-3)= 200
y=200x+b
Plug in any point to find b
2000=200(3)+b
b=1400
so your equation is y=200x+1400
:P
Looks like a straight line of slope (600/3) to me since fees increase 600 for every three credits.
F = 200 C + b solve for b
2000 = 200 (3) + b
2000 = 600 + b
b = 1400
so
Fee = 200 (Credits) + 1400
check with (15 , 4400)
4400 = (200)(15) + 1400 ?????
4400 = 3000 + 1400 ???? YES, check
Now do
Fee = 200 (17) + 1400 for part b
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