Posted by Daisy on .
A speeder passes a parked police car at a
constant speed of 31.8 m/s. At that instant,
the police car starts from rest with a uniform
acceleration of 2.74 m/s
How much time passes before the speeder
is overtaken by the police car?
t=2v/a=2•31.2/2.74= 22.8 s