Posted by monae on Saturday, September 1, 2012 at 11:02am.
How fast would a ball have to be thrown upward to reach a maximum height of 49 ft? [Hint: Use the discriminant of the equation
16t2 − v0t + h = 0.

math  Anu, Saturday, September 1, 2012 at 8:03pm
This equation is derived from the following:
at maximum height the velocity is zero.
y(current height)= y0 (initial height)+v0t+.5at^2
take the derivative
32tv0=0 so vo=32t
Plug this in for the v0 value
16t2 − (32t)t + h = 0
h=49ft
16t^2+49=0
Solve for t:
16t^2=49
4t=7
t=7/4
Plug in t and h to solve for v0
16t2 − v0t + h = 0 where h=49 and t=7/4
16(7/4)^2v0 (7/4) +49=0
:P

math  Amber, Tuesday, January 21, 2014 at 2:46pm
How fast would a ball have to be thrown upward to reach a maximum height of 49 ft? [Hint: Use the discriminant of the equation 16t2 − v0t + h = 0.]
Answer This Question
Related Questions
 algebra  A ball is thrown into the air with an upward velocity of 28 ft/s. Its ...
 Algebra  A ball is thrown into the air with an upward velocity of 28 ft/s. Its...
 PreCalculas  A ball is thrown upward with an initial velocity of 4 ft/sec from ...
 algebra 2  So the dead line for my class is coming up. And I really need help ...
 Algebra  The equation h= 16t^2 + 32t + 9 gives the height of a ball, h, in ...
 Algebra  The equation h = 16t^2 + 32t + 9 gives the height of a ball, h, in ...
 algebra 2  A ball is thrown directly upward from an initial height of 200 feet ...
 Math  In physics, one learns that the height of an object thrown upward from an...
 math  2. How is the graph of y = –2x² – 5 different from the graph of y = –2x...
 PreCalculus  A ball is thrown up at the edge of a 364 foot cliff. The ball is ...
More Related Questions