Posted by Yeneta on .
A solution contains 15 g non-volatile non-electrolyte solute C6H14O6 dissolved in 500 g of water at 40 c.
(A)Vapor pressure of the solution.
(B)Boiling point of the solution.
(C)Freezing point of the solution.
b. mols C6H14O6 = grams/molar mass.
Substitute mols into
molality = mols/kg solvent and solve for m, then substitute m into
delta T = Kb*m, solve for delta T and add to the normal boiling point for H2O.
c. Use calculation for mols and molality from above and substitute into
delta T = Kf*m and solve for delta T and subtract from normal freezing point of H2O.
a. Psoln = XH2O*PoH2O
where XH2O = mols H2O/total mols.