H2SO4 solution containing 200.1 g of H2SO4 in 0.3500 L OF solution has a density of 1.3294 g/ml.calculate

(A) Mass%H2SO4(m/m)
(B)mass%H2O(m/m)
(C)Molarity
(D)Molality

a. mass H2SO4 = 200.1g

mass soln = 1.3294 g/mL x 350.0 mL = ?grams.
mass% H2SO4 = (mass H2SO4/total mass)*100 = ?

b. mass H2O = mass soln - mass H2SO4.
mass% H2O = (mass H2O/mass soln)*100 = ?
Note: Also 100%-%H2SO4 = %H2O.

c. M = mols H2SO4/L soln (mols H2SO4 = 200.1/molar mass H2SO4).

d. m = mols/kg solvent. mass solvent you can get from b.

To calculate the requested values, we'll need to use the given information and formulas related to the concepts of mass percent, density, molarity, and molality. Let's break down each part and calculate them step by step:

(A) Mass%H2SO4 (m/m):
Mass percent (m/m) is calculated by dividing the mass of the solute by the mass of the entire solution and multiplying by 100.

Mass of H2SO4 in solution = 200.1 g
Mass of solution = Density × Volume
= 1.3294 g/ml × 0.3500 L
= 0.4652 g

Mass%H2SO4 (m/m) = (Mass of H2SO4 / Mass of Solution) × 100
= (200.1 g / 0.4652 g) × 100

Therefore, the Mass%H2SO4 (m/m) is equal to (200.1 / 0.4652) × 100.

(B) Mass%H2O (m/m):
Since H2SO4 is the solute and the rest is water, we can calculate the Mass%H2O (m/m) by subtracting the Mass%H2SO4 (m/m) from 100%.

Mass%H2O (m/m) = 100% - Mass%H2SO4 (m/m)

(C) Molarity:
Molarity is calculated by dividing the number of moles of solute (H2SO4) by the volume of the solution in liters.

First, we need to determine the number of moles of H2SO4.
Number of moles = Mass / Molar mass

Molar mass of H2SO4 = (2 × atomic mass of H) + (1 × atomic mass of S) + (4 × atomic mass of O)
= (2 × 1.00794 g/mol) + (32.06 g/mol) + (4 × 16.00 g/mol)
= 98.09 g/mol

Number of moles of H2SO4 = Mass of H2SO4 / Molar mass
= 200.1 g / 98.09 g/mol

Now, we can calculate the Molarity using the number of moles and the volume of the solution.
Molarity (M) = Number of moles / Volume of solution (in liters)
= (200.1 g / 98.09 g/mol) / 0.3500 L

(D) Molality:
Molality is calculated by dividing the number of moles of solute (H2SO4) by the mass of the solvent (in kg).

Number of moles of H2SO4 = Mass of H2SO4 / Molar mass (already calculated)

Mass of water (solvent) = Mass of solution - Mass of H2SO4
= Mass of solution - Density × Volume
= 0.4652 g - (1.3294 g/ml × 0.3500 L)

Now we can calculate Molality using the number of moles and the mass of the solvent (in kg).
Molality (m) = Number of moles / Mass of solvent (in kg)
= Number of moles / (Mass of water / 1000)

After calculating the steps mentioned above, you will have the values for (A) Mass%H2SO4 (m/m), (B) Mass%H2O (m/m), (C) Molarity, and (D) Molality.