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April 18, 2014

April 18, 2014

Posted by **Miaow** on Friday, August 31, 2012 at 7:31pm.

A student drove to the university from her home and noted that the odometer reading of her car increased by 12.0 km. The trip took 18.0 min. (a) What was her average speed? (b) If the straight-line distance from her home to the university is 10.3 km in a direction 25.0o south of

east, what was her average velocity? (c) If she returned home by the same path 7 h 30 min after she left, what were her average speed and velocity for the entire trip?

a.) average speed: 12 km/18 min=0.67 km/min

b.) average velocity: (must find time first)

t: 10.3 km/ 0.67 km = 15.4 min

average velocity: 10.3 km/15.4 min = 0.67 km/min

c.) average speed: 24 km/450 min = 0.05 km/min

average velocity: 0 km/450 min = 0

- Physics -
**MathMate**, Friday, August 31, 2012 at 8:24pm(a) we usually express car speeds in km/hour

(b) Displacement = 10.3 km in direction 25° S of east

Time = 18 min = 0.3 hour

So velocity = 34.3 km/hr in direction 25° S of E.

(c)Correct.

- Physics -
**Miaow**, Friday, August 31, 2012 at 8:54pmThank you very much!

I wondered if I should switch to km/hr. And, I was SURE I was wrong on B but AMAZED I was right on C. :)

- Physics :) -
**MathMate**, Saturday, September 1, 2012 at 6:23amYou're welcome!

Yes, velocity is a vector, so it is described by the magnitude (speed) and direction.

The same goes for displacement, which is also a vector, and therefore is described by the magnitude and direction.

Keep up the good work!

- Physics -
**julie**, Wednesday, September 5, 2012 at 6:10pmso i got all answers but part c for average velocity is zero since there is no info about the displacement?

- Physics -
**MathMate**, Wednesday, September 5, 2012 at 7:34pmFor part c, you put average speed as 0.05 km/min, which is correct.

Subsequently, as part 2 of (c), you did put average velocity as 0.

Perhaps there was a confusion of the questions.

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