physics
posted by J.A. on .
if the radius of the earth is 6.37 times 10 to the third power in km, what is the speed in km/h resulting from the rotation of earth of a person standing on the equater. then, convert the answer to m/s.

circumference of earth = 2pi*6.37*10^3 km = 4.00*10^4 km
so, a person travels that many km in 24 hours:
4.00*10^4km/24hr = 1667.66km/hr
to get m/s, just multiply by the needed units:
1667.66km/hr * 1000m/km * 1hr/3600s = 463.24m/s