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January 31, 2015

January 31, 2015

Posted by **Angel** on Friday, August 31, 2012 at 2:33pm.

A commonly used rule of thumb is that average velocity in a pipe should be about 1 m/s or less for "thin"(viscosity about water). If a pipe needs to deliver 6,000 m^3 of water a day, what diameter is required to satisfy the 1 m/s rule

- Chemistry/Math -
**Steve**, Friday, August 31, 2012 at 4:43pmif the diameter is d meters, the cross-section of the pipe has area pi/4 d^2 m^2

In one second, at 1 m/s, then, pi/4 d^2 m^3/s of water will flow through the pipe

now just plug in the numbers:

6000m^3/day * 1day/86400s = pi/4 d^2 m^3/s

d = 1/3 √(5/2pi) = 0.297m

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