posted by Mariam on .
A car starts from rest and moves with constant acceleration during the 5th second of its motion,it covers a distance of 36 meters. what is the acceleration
since s = 1/2 at^2, then during 4 <=t <=5 (the 5th second)
36 = 1/2 a 5^2 - 1/2 a 4^2 = 9/2 a
a = 8
Thnx a lot steve
it means car have 8 m/s^2 constant acceleration.
Then what do you think steve if we put this acceleration to calculate exact time period which will be greater than 4 seconds?
If we have to find the total distance also then how we'll do it???