A plane traveling at 80 m/s lands on a runway and comes to rest after 10 seconds. What was the plane's deceleration
the velocity went from 80m/s in 10 seconds
acceleration is thus -80m/s / 10s = -8m/s^2
0-80/10=-8
To find the plane's deceleration, we can use the formula:
acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 80 m/s
Final velocity (v) = 0 m/s
Time taken (t) = 10 seconds
Substituting these values into the formula:
acceleration = (0 - 80) / 10
Simplifying:
acceleration = -80 / 10
acceleration = -8 m/s²
Therefore, the plane's deceleration was -8 m/s².
To find the plane's deceleration, we can use the kinematic equation:
\[ v = u + at \]
where:
v = final velocity (0 m/s, since the plane comes to rest)
u = initial velocity (80 m/s)
a = deceleration (what we need to find)
t = time (10 seconds)
Rearranging the equation to solve for acceleration (a):
\[ a = \frac{{v - u}}{t} \]
Substituting the given values:
\[ a = \frac{{0 - 80}}{10} \]
Simplifying:
\[ a = \frac{{-80}}{10} \]
Calculating:
\[ a = -8 \, \text{m/s}^2 \]
Therefore, the plane's deceleration is -8 m/s². The negative sign indicates that the deceleration is in the opposite direction of the initial velocity.