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Math

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Draw a diagram to solve this problem: Ajax is 8 km due west of Oshawa. Uxbridge is 6 km NW of Oshawa. How far is it from Ajax to Uxbridge? Explain whether you have enough information to solve this problem?

  • Math - ,

    Draw the -8km vector from the origin on the neg. x-axis.

    Draw the 6km vector from the origin 45o
    west of north(135o).

    Du = 6km @ 135o.
    Du = 6*cos135 + i6*sin135
    Du = -4.24 + i4.24 = Dist. from Oshawa
    to Uxbridge.

    Da = -8 km=Dist. from Oshawa to Ajax.

    D = Du - Da
    D = (-4.24+i4.24) - (-8)
    D = 3.76 + i4.24
    D^2 = (3.76)^2 + (4.24)^2 = 32.12
    D = 5.67 km.

  • Math - ,

    post it.

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