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August 1, 2014

August 1, 2014

Posted by **Danielle** on Friday, August 31, 2012 at 1:52am.

- Math -
**Henry**, Sunday, September 2, 2012 at 11:14pmDraw the -8km vector from the origin on the neg. x-axis.

Draw the 6km vector from the origin 45o

west of north(135o).

Du = 6km @ 135o.

Du = 6*cos135 + i6*sin135

Du = -4.24 + i4.24 = Dist. from Oshawa

to Uxbridge.

Da = -8 km=Dist. from Oshawa to Ajax.

D = Du - Da

D = (-4.24+i4.24) - (-8)

D = 3.76 + i4.24

D^2 = (3.76)^2 + (4.24)^2 = 32.12

D = 5.67 km.

- Math -
**Henry**, Sunday, September 2, 2012 at 11:17pmpost it.

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