Math
posted by Danielle on .
Draw a diagram to solve this problem: Ajax is 8 km due west of Oshawa. Uxbridge is 6 km NW of Oshawa. How far is it from Ajax to Uxbridge? Explain whether you have enough information to solve this problem?

Draw the 8km vector from the origin on the neg. xaxis.
Draw the 6km vector from the origin 45o
west of north(135o).
Du = 6km @ 135o.
Du = 6*cos135 + i6*sin135
Du = 4.24 + i4.24 = Dist. from Oshawa
to Uxbridge.
Da = 8 km=Dist. from Oshawa to Ajax.
D = Du  Da
D = (4.24+i4.24)  (8)
D = 3.76 + i4.24
D^2 = (3.76)^2 + (4.24)^2 = 32.12
D = 5.67 km. 
post it.