Posted by jennifer on Thursday, August 30, 2012 at 11:20pm.
(y^2)^4y^8 simplify

pre cal  victor_hery, Friday, August 31, 2012 at 12:30am
y^2  4y^8 = y^2  (2y^4)^2
= (y + 2y^4)(y  2y^4)
formulas a^2  b^2 = (a + b)(a  b)

pre cal  Steve, Friday, August 31, 2012 at 12:50pm
Or, seeing that the expression as written is meaningless, and assuming the usual carelessness with parentheses,
(y^2)^(4) * y^8
= y^(2 * 4) * y^8
= y^(8) * y^8
= y^(8+8)
= y^0
= 1
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