Posted by jennifer on Thursday, August 30, 2012 at 11:20pm.
pre cal - victor_hery, Friday, August 31, 2012 at 12:30am
y^2 - 4y^8 = y^2 - (2y^4)^2
= (y + 2y^4)(y - 2y^4)
formulas a^2 - b^2 = (a + b)(a - b)
pre cal - Steve, Friday, August 31, 2012 at 12:50pm
Or, seeing that the expression as written is meaningless, and assuming the usual carelessness with parentheses,
(y^2)^(-4) * y^8
= y^(2 * -4) * y^8
= y^(-8) * y^8
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