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December 20, 2014

December 20, 2014

Posted by **jennifer** on Thursday, August 30, 2012 at 11:20pm.

- pre cal -
**victor_hery**, Friday, August 31, 2012 at 12:30amy^2 - 4y^8 = y^2 - (2y^4)^2

= (y + 2y^4)(y - 2y^4)

formulas a^2 - b^2 = (a + b)(a - b)

- pre cal -
**Steve**, Friday, August 31, 2012 at 12:50pmOr, seeing that the expression as written is meaningless, and assuming the usual carelessness with parentheses,

(y^2)^(-4) * y^8

= y^(2 * -4) * y^8

= y^(-8) * y^8

= y^(-8+8)

= y^0

= 1

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