Posted by jennifer on .
(y^2)^4y^8 simplify

pre cal 
victor_hery,
y^2  4y^8 = y^2  (2y^4)^2
= (y + 2y^4)(y  2y^4)
formulas a^2  b^2 = (a + b)(a  b) 
pre cal 
Steve,
Or, seeing that the expression as written is meaningless, and assuming the usual carelessness with parentheses,
(y^2)^(4) * y^8
= y^(2 * 4) * y^8
= y^(8) * y^8
= y^(8+8)
= y^0
= 1