Wednesday

August 27, 2014

August 27, 2014

Posted by **jennifer** on Thursday, August 30, 2012 at 11:20pm.

- pre cal -
**victor_hery**, Friday, August 31, 2012 at 12:30amy^2 - 4y^8 = y^2 - (2y^4)^2

= (y + 2y^4)(y - 2y^4)

formulas a^2 - b^2 = (a + b)(a - b)

- pre cal -
**Steve**, Friday, August 31, 2012 at 12:50pmOr, seeing that the expression as written is meaningless, and assuming the usual carelessness with parentheses,

(y^2)^(-4) * y^8

= y^(2 * -4) * y^8

= y^(-8) * y^8

= y^(-8+8)

= y^0

= 1

**Related Questions**

Pre Cal - simplify the quotient: [x(5x+1)-3(x^2+1)]/ [(x-1)^2]

Pre-Cal - Simplify e^3ln2-1

Pre Cal - simplify the quotient: [(x+1)^3(4x-9)-(16x+9)(x+1)^2]/[(x-6)(x+1)^3]

PRE-CAL - SIMPLIFY 55/SQUARE ROOT OF 20 -3

Pre Cal - simplify the expression 2sin^2 t + cos^2 t-2

Pre-Cal - For given functions f and g find formulas for a)f o g and b)g o f. ...

pre-cal - can anyone please explain to me how to simplify this exponential ...

Pre-cal - Simplify: A) log(x+1)+3logx B) 2log4np-3log4p C) 2ln(3x)+ln(5x)-ln6xy ...

Math (College Pre-Cal) - For given functions f and g find formulas for a)f o g ...

Pre-Cal - 1)(1-cos^2x)(csc x) ? Is this equal to sec x? 2) Expand: log7 3 sqrt x...